Answer:
Step-by-step explanation:
[tex]Q1:\\8-5(3x-7)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=8-(5)(3x)+(-5)(-7)=8-15x+35=-15x+(8+35)\\=\boxed{-15x+43}[/tex]
[tex]Q2:\\6(2x+3)-4(5x+2)\qquad\text{use the distributive property}\\\\=(6)(2x)+(6)(3)+(-4)(5x)+(-4)(2)=12x+18-20x-8\\\\\text{combine like terms}\\\\=(12x-20x)+(18-8)=\boxed{-8x+10}[/tex]
[tex]Q3.\\4(x+5)+4x+8\qquad\text{use the distributive property}\\\\=(4)(x)+(4)(5)+4x+8=4x+20+4x+8\\\\\text{combine like terms}\\\\=(4x+4x)+(20+8)=\boxed{8x+28}=(4)(2x)+(4)(7)=\boxed{4(2x+7)}[/tex]