Answer:
[tex]\frac{38}{7}[/tex]
Step-by-step explanation:
Using the properties of logarithms,
[tex]\log(7)+\log(x-4)=1\\\log(7(x-4))=1\\\log(7x-28)[/tex]
Now think about what this is asking. The log function say 10 to the power of whats on the other side of the equals sign, equals whats in the parenthesis. So, this means whats is the parenthesis is equal to [tex]10^1[/tex] or just 10.
We can now solve to x.
[tex]7x-28 = 10\\7x=38\\x=\frac{38}{7}[/tex]
