Find the inverse of the following function.

For this case we must find the inverse of the following function:
[tex]f (x) = \sqrt [3] {x + 12}[/tex]
For this, we follow the steps below:
Replace f (x) with y:
[tex]y = \sqrt [3] {x + 12}[/tex]
We exchange the variables:
[tex]x = \sqrt [3] {y + 12}[/tex]
We solve the equation for "and":
[tex]\sqrt [3] {y + 12} = x[/tex]
We raise both sides of the equation to the cube to eliminate the root:
[tex](\sqrt [3] {y + 12}) = x ^ 3\\y + 12 = x ^ 3[/tex]
We subtract 12 on both sides of the equation:
[tex]y = x ^ 3-12[/tex]
Thus, the inverse function is:
[tex]f ^ {- 1} = x ^ 3-12[/tex]
Answer:
Option B
Option: B is the correct answer.
B. [tex]f^{-1}(x)=x^3-12[/tex]
The inverse function f(x) is calculated in the following steps.
The function f(x) is given by:
[tex]f(x)=\sqrt[3]{x+12}[/tex]
Now, we keep:
[tex]f(x)=y\\\\i.e.\\\\y=\sqrt[3]{x+12}[/tex]
Now, we interchange x and y
[tex]x=\sqrt[3]{y+12}[/tex]
Now, on taking cube on both side of the equation we have:
[tex]y+12=x^3\\\\i.e.\\\\y=x^3-12[/tex]
i.e.
[tex]f^{-1}(x)=x^3-12[/tex]