Answer:
The specific weight is [tex]1.5\frac{g}{cm^{3}}[/tex]
Step-by-step explanation:
The question in English
A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed
step 1
Find the radius of the cone
we know that
The lateral area of a cone is equal to
[tex]LA=\pi rl[/tex]
we have
[tex]LA=255\pi\ cm^{2}[/tex]
[tex]l=17\ cm[/tex]
substitute the values
[tex]255\pi=\pi r(17)[/tex]
Simplify
[tex]255=r(17)[/tex]
[tex]r=255/(17)=15\ cm[/tex]
step 2
Find the height of the cone
Applying the Pythagoras Theorem
[tex]l^{2} =r^{2} +h^{2}[/tex]
substitute the values and solve for h
[tex]17^{2} =15^{2} +h^{2}[/tex]
[tex]h^{2}=17^{2}-15^{2}[/tex]
[tex]h^{2}=64[/tex]
[tex]h=8\ cm[/tex]
step 3
Find the volume of the cone
The volume of the cone is equal to
[tex]V=\frac{1}{3}\pi r^{2}h[/tex]
substitute the values
[tex]V=\frac{1}{3}\pi (15)^{2}(8)[/tex]
[tex]V=600\pi\ cm^{3}[/tex]
step 4
Find the specific weight
Divide the mass by the volume
[tex]\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}[/tex]