Drag each triangle to the correct category.
For each set of side lengths, classify the triangle based on whether it is a right triangle.

1. 4,10,11

2. 4,4 square root of 32

3. 8,7, square root of 113

4. 4,4 square root of 24

5. 7,8,15


What is a right triangle and which is not a right triangle

Respuesta :

Answer:

[tex]4,10,11[/tex] not Right Triangle

[tex]4, 4, \sqrt{32}[/tex] Right Triangle

[tex]8, 7, \sqrt{113}[/tex] Right Triangle.

[tex]4, 4, \sqrt{24}[/tex] not Right Triangle.

[tex]7, 8, 15[/tex] not Right Triangle.

Step-by-step explanation:

To determine if a set of side lengths corresponds to a right triangle, the sides must satisfy the Pitagorean identity:

[tex]side1^{2} + side2^{2} = hypotenuse^{2}[/tex]

Notice that the hypotenuse is always the greatest side of the set...

Let's plug the given values into the idenity above.

Option 1

[tex]4^{2} + 10^{2} =_{?} 11^{2}[/tex]

[tex]16 + 100 =_{?} 121[/tex]

[tex]116 \neq 121[/tex]

Option 2

[tex]4^{2} + 4^{2} =_{?} (\sqrt{32})^{2}[/tex]

[tex]16 + 16 =_{?} 32[/tex]

[tex]32 = 32[/tex]

Option 3

[tex]8^{2} + 7^{2} =_{?} (\sqrt{113})^{2}[/tex]

[tex]64 + 49 =_{?} 113[/tex]

[tex]113 = 113[/tex]

Option 4

[tex]4^{2} + 4^{2} =_{?} (\sqrt{24})^{2}[/tex]

[tex]16 + 16 =_{?} 24[/tex]

[tex]32 \neq 24[/tex]

Option 5

[tex]7^{2} + 8^{2} =_{?} 15^{2}[/tex]

[tex]49 + 64 =_{?} 225[/tex]

[tex]113 \neq 121[/tex]

Answer:

see picture

Step-by-step explanation:

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