Question

How much heat in kilojoules has to be removed from 225g of water to lower its temperature from 25.0oC to 10.0oC?

Answer 1

Answer:

14108 J

Explanation:

The heat that has to be removed from the water is given by

$Q=m C_s \Delta T$

where

m = 225 g is the water mass

$C_s = 4.18 J/gC$ is the specific heat capacity of the water

$\Delta T=10.0 C-25.0 C=-15.0 C$ is the charge in temperature of the water

Substituting into the equation, we find

$Q=(225 g) (4.18 J/gC) (-15.0 C)=-14,108 J$

and the negative sign means the heat is removed from the system.