Answer :
[tex]SA=(2)\pi (3)^{2}+ 2\pi (3)(14)[/tex]
Step-by-step explanation:
we know that
The surface area of a cylinder is equal to
[tex]SA=2\pi r^{2}+ 2\pi rh[/tex]
we have
[tex]r=6/2=3\ cm[/tex] ----> the radius is half the diameter
[tex]h=14\ cm[/tex]
substitute the values
[tex]SA=(2)\pi (3)^{2}+ 2\pi (3)(14)[/tex]