Respuesta :
Answer:
Function 1 has the least minimum value and its coordinates are (2, -7).
Step-by-step explanation:
Two quadratic functions are shown.
Function 1:
[tex]f(x) = 2x^2 - 8x + 1[/tex]
Function 2:
x g(x)
-2 2
-1 -3
0 2
1 17
LEts find the vertex to get the minimum value
to get the minimum value for function 1 we use formula [tex]x=\frac{-b}{2a}[/tex]
[tex]f(x) = 2x^2 - 8x + 1[/tex], a=2, b=-8
[tex]x=\frac{-b}{2a}=\frac{8}{2(2)}=2[/tex]
when x=2, the value of [tex]f(2) = 2(2)^2 - 8(2) + 1=-7[/tex]
minimum point of function 1 is (2,-7)
For function 2, we find the minimum point using the table
minimum point of function 2 is (-1,-3)
Function 1 has the least minimum -7.
Function 1 has the least minimum value and its coordinates are (2, -7).
The true statement is (b) function 1 has the least minimum value and its coordinates are (2, -7).
The first quadratic function is given as:
- [tex]f(x)= 2x^2 - 8x +1[/tex]
Factor out 2 in the above equation
[tex]f(x)= 2(x^2 - 4x) +1[/tex]
Rewrite the expression in the bracket, as follows:
[tex]f(x)= 2(x^2 - 4x + 4 - 4) +1[/tex]
This gives
[tex]f(x)= 2(x^2 - 4x + 4 ) -8+1[/tex]
[tex]f(x)= 2(x^2 - 4x + 4 ) -7[/tex]
Express x^2 - 4x + 4 as a perfect square
[tex]f(x)= 2(x - 2)^2 -7[/tex]
A quadratic function is represented as:
[tex]f(x)= a(x - h)^2 +k[/tex]
Where
[tex]Vertex = (h,k)[/tex]
By comparison, we have:
- [tex]Vertex = (2,-7)[/tex] --- this represents the minimum of function 1
From the graph, the minimum of function 2 is:
- [tex]Vertex = (-1,-3)[/tex]
(2,-7) is lesser than (-1,-3).
Hence, the function 1 has the least minimum value at a coordinate of (2,-7)
Read more about quadratic functions at:
https://brainly.com/question/11631534