Question

Calculate [H3O+

] of a 0.150 M acetic acid solution.​

Answer 1

Answer:

[H3O+] = 0.00520 M

Explanation:

The dissociation of acetic acid in water is given by the equation;

CH3COOH + H2O<-------> H3O+ + CH3COO-  

ka =  [H+][C2H3O2-]/[HC2H3O2]

Ka = 1.8 x 10^-5

      = x^2 / 0.150-x  

x = [H3O+]= 0.00520 M