Respuesta :
if the cone has a diameter of 12, thus its radius is half that, namely 6.
[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=6\\ h=20 \end{cases}\implies V=\cfrac{\pi (6)^2(20)}{3}\implies V=240\pi \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 753.98~\hfill[/tex]
