Question

On a map of campground, the swimming pool is located at (2, -3 ), the camp store at ( 2, 8), and the tent at ( -7, 8 ). If each unit represents 5 feet , how many feet will it be to walk from the tent to the store and then to the pool? Please show the work, thank you !

Answer 1

Answer:

$100\ ft$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Let

A(-7,8) -----> coordinates of the tent

B(2,8) ----> coordinates of the store

C(2,-3) ----> coordinates of the swimming pool

step 1

Find the distance from the tent to the store

$A(-7,8),B(2,8)$

substitute in the formula

$dAB=\sqrt{(8-8)^{2}+(2+7)^{2}}$

$dAB=\sqrt{(0)^{2}+(9)^{2}}$

$dAB=9\ units$

step 2

Find the distance from the store to the pool

$B(2,8),C(2,-3)$

substitute in the formula

$dBC=\sqrt{(-3-8)^{2}+(2-2)^{2}}$

$dBC=\sqrt{(-11)^{2}+(0)^{2}}$

$dBC=11\ units$

step 3

Adds the distances

$9\ units+11\ units=20\ units$

Convert to feet

$20\ units=20*5=100\ ft$