Answer:
The base is [tex]11\ in[/tex] and the height is [tex]14\ in[/tex]
Step-by-step explanation:
we know that
The area of the triangle is equal to
[tex]A=\frac{1}{2}(b)(h)[/tex]
where
b is the base of triangle
h is the height of triangle
In this problem
[tex]b=h-3[/tex] ----> equation A
[tex]A=77\ in^{2}[/tex]
so
[tex]77=\frac{1}{2}(b)(h)[/tex]
[tex]154=(b)(h)[/tex] -----> equation B
Substitute equation A in equation B
[tex]154=(h-3)(h)[/tex]
[tex]h^{2}-3h-154=0[/tex]
Solve the quadratic equation by graphing
The solution is [tex]h=14\ in[/tex]
see the attached figure
Find the base b
[tex]b=14-3=11\ in[/tex]