Respuesta :

Answer: [tex]y-\frac{1}{2}=-(x+\frac{1}{2})[/tex]

Step-by-step explanation:

The point-slope form of the equation of the line is:

[tex]y-y_1=m(x-x_1)[/tex]

Where "m" is the slope of the line and [tex](x_1,y_1)[/tex] is a point of the line.

You know the value of the slope and you also know a point of the line, then you need to substitute values into [tex]y-y_1=m(x-x_1)[/tex].

Therefore, you get that the equation of this line in  point-slope form is:

[tex]y-\frac{1}{2}=-1(x-(-\frac{1}{2})\\\\y-\frac{1}{2}=-(x+\frac{1}{2})[/tex]

Answer:

y = -x

Step-by-step explanation:

Given in the question,

co-ordinate(-1/2 , 1/2)

gradient of the line = -1

Standard equation form of a straight line

y - y1 = m(x - x1)

here y1 = 1/2

        x1 = -1/2

        m = -1

Plug values in the equation

y - 1/2 = -1(x + 1/2)

y -1/2 = -x - 1/2

y = -x

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