Respuesta :
Answer: [tex]y-\frac{1}{2}=-(x+\frac{1}{2})[/tex]
Step-by-step explanation:
The point-slope form of the equation of the line is:
[tex]y-y_1=m(x-x_1)[/tex]
Where "m" is the slope of the line and [tex](x_1,y_1)[/tex] is a point of the line.
You know the value of the slope and you also know a point of the line, then you need to substitute values into [tex]y-y_1=m(x-x_1)[/tex].
Therefore, you get that the equation of this line in point-slope form is:
[tex]y-\frac{1}{2}=-1(x-(-\frac{1}{2})\\\\y-\frac{1}{2}=-(x+\frac{1}{2})[/tex]
Answer:
y = -x
Step-by-step explanation:
Given in the question,
co-ordinate(-1/2 , 1/2)
gradient of the line = -1
Standard equation form of a straight line
y - y1 = m(x - x1)
here y1 = 1/2
x1 = -1/2
m = -1
Plug values in the equation
y - 1/2 = -1(x + 1/2)
y -1/2 = -x - 1/2
y = -x