Answer:
3
Step-by-step explanation:
Using the rules of logarithms.
• log x - log y ⇒ log([tex]\frac{x}{y}[/tex])
• [tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
[tex]log_{3}[/tex]108 - [tex]log_{3}[/tex] 4 = [tex]log_{3}[/tex]([tex]\frac{108}{4}[/tex]) = [tex]log_{3}[/tex] 27 = n
Hence
27 = [tex]3^{n}[/tex], that is
[tex]3^{3}[/tex] = [tex]3^{n}[/tex]
Since bases on both sides are 3 , equate the exponents
n = 3
