Answer:
x = 0 or x = -8
Step-by-step explanation:
[tex]8x^2+64x=0\qquad\text{divide both sides by 8}\\\\\dfrac{8\!\!\!\!\diagup x^2}{8\!\!\!\!\diagup}+\dfrac{64\!\!\!\!\!\diagup^8 x}{8\!\!\!\!\diagup}=\dfrac{0}{8}\\\\x^2+8x=0\qquad\text{distribute}\\\\x(x+8)=0\iff x=0\ or\ x+8=0\\\\x+8=0\qquad\text{subtract 8 from both sides}\\x=-8[/tex]
