Question

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

Answer 1

For this case we have the following quadratic equation:

$0 = -3x ^ 2-2x + 6$

Where:

$a = -3\\b = -2\\c = 6$

The quadratic formula, to find the roots, is given by:$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Substituting the values:

$x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (-3) (6)}} {2 (-3)}\\x = \frac {2 \pm \sqrt {(- 2) ^ 2 + 4 (3) (6)}} {2 (-3)}$

Answer:

$x = \frac {2 \pm \sqrt {(- 2) ^ 2 + 4 (3) (6)}} {2 (-3)}$

Answer 2

0=-3x^2-2x+6

Step-by-step explanation:

A on edge2020