Answer:
= 135,647.65 Joules or 135.65 kJ
Explanation:
Heat require to raise the temperature of 55 g water from 62.5°C to 124.0°C will be calculated in steps;
Step 1; heat required to raise water from 62.5°C to 100 °C
Heat = 55 g × 4.18 J/g°C × (100 -62.5)
= 8,621.25 Joules
Step 2; Heat required to convert water to steam without change in temperature;
Heat = moles × Molar Latent heat of vaporization.
= (55g / 18 g/mol)× 4.07 ✕ 104 J/mol
= 12.436 × 10^4 Joules
Step 3: Heat required to raise the temperature of steam from 100°C to 124 °C.
Heat = mass × specific heat capacity × ΔT
= 55 g × 2.02 J/g°C × (124-100)
= 2,666.4 Joules
Therefore; total amount of heat required is;
= 8,621.25 J + 124360 J + 2,666.4 J
= 135,647.65 Joules or 135.65 kJ
