In the triangle shown, what is the value of x

Answer:
b 4 sqrt(2) cm
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2, where a and b are the legs
x^2 + x^2 = 8^2
2x^2 = 62
Divide each side by 2
2x^2/2 = 64/2
x^2 =32
Take the square root of each side
sqrt(x^2) = sqrt(32)
x = sqrt(16*2)
We know that sqrt(a*b)= sqrt(a) sqrt(b)
x = sqrt(16) sqrt(2)
x = 4sqrt(2)