Answer:
60.77°C.
Explanation:
Q = m.c.ΔT.
where, Q is the amount of heat absorbed by Ni (Q = 328 J),
m is the mass of Ni (m = 16.7 g),
c is the specific heat capacity of Ni (c = 0.54 J/g °C),
ΔT is the temperature difference (final T - initial T) (ΔT = final T - 24.4°C).
∵ Q = m.c.ΔT.
∴ (328 J) = (16.7 g)(0.54 J/g °C)(final T - 24.4°C)
(final T - 24.4°C) = (328 J)/(16.7 g)(0.54 J/g °C) = 36.37°C.
∴ final T = 36.37°C + 24.4°C = 60.77°C.