Answer:
The area of triangle is 19.8 square units
Option B is correct.
Step-by-step explanation:
Given the triangle ABC in which
AB=6.8 units, BC=5.9 units and ∠B=99°
we have to find the area of triangle.
c=6.8 units and a=5.9 units
The area of triangle can be calculated as
[tex]Area=\frac{1}{2}ac\sin \angle B[/tex]
[tex]=\frac{1}{2}\times 5.9\times 6.8\times \sin 99^{\circ}[/tex]
[tex]=20.06\times \sin 99^{\circ}=19.813\sim 19.8 units^2[/tex]
The area of triangle is 19.8 square units
Option B is correct.
