Answer: Third Option
yes; k = 4 and y = 4x
Step-by-step explanation:
Observe in the values of x and y given that when x decreases the variable-y also decreases.
Then the variation is direct.
Then, if between any two points of the function, the rate of variation k remains the same then the variation is constant.
We can test whether these conditions are met by using the given points.
(-2, -8) and (-4, -16)
The rate of variation k for these points is:
[tex]k = \frac{y_2-y_1}{x_2-x_1}\\\\k =\frac{-16-(-8)}{-4-(-2)}\\\\k = \frac{-16+8}{-4+2}\\\\k =4[/tex]
Now we calculate the variation rate for the points
(-4, -16) and (-6, -24)
[tex]k = \frac{y_2-y_1}{x_2-x_1}\\\\k =\frac{-24-(-16)}{-6-(-4)}\\\\k = \frac{-24+16}{-6+4}\\\\k =4[/tex]
The rate of variation is constant and equal to 4.
Then the answer is yes; k = 4 and y = 4x