Answer:
Part a) The area of the garden will be [tex]159\frac{4}{9}\ ft^{2}[/tex]
Part b) [tex]33\%[/tex]
Step-by-step explanation:
step 1
Find the area of the original garden
The area is equal to
[tex]A=LW[/tex]
we have
[tex]L=10\ ft[/tex]
[tex]W=12\ ft[/tex]
substitute
[tex]A=(10)(12)=120\ ft^{2}[/tex]
step 2
Find the area of the expanded garden
we know that
[tex]1\frac{2}{3}\ ft=\frac{5}{3}\ ft[/tex]
so
[tex]L=(10+\frac{5}{3})=\frac{35}{3}\ ft[/tex]
[tex]W=(12+\frac{5}{3})=\frac{41}{3}\ ft[/tex]
The new area is
[tex]A=(\frac{35}{3})(\frac{41}{3})=\frac{1,435}{9}\ ft^{2}[/tex]
Convert to mixed number
[tex]\frac{1,435}{9}\ ft^{2}=\frac{1,431}{9}+\frac{4}{9}=159\frac{4}{9}\ ft^{2}[/tex]
step 3
Divide the expanded area by the original area
[tex](\frac{1,435}{9})/120=1.33[/tex]
Convert to percentage
[tex]1.33*100=133\%[/tex]
therefore
The percent that the garden has grown is
[tex]133\%-100\%=33\%[/tex]