Respuesta :

gmany

Answer:

[tex]\large\boxed{d\geq-3}[/tex]

Step-by-step explanation:

[tex]11d-9\leq15d+3\qquad\text{add 9 to both sides}\\\\11d\leq15d+12\qquad\text{subtract 15d from both sides}\\\\-4d\leq12\qquad\text{change the signs}\\\\4d\geq-12\qquad\text{divide both sides by 4}\\\\d\geq-3[/tex]

Answer:

d ≥ -3

Step-by-step explanation:

11d - 9≤ 15d + 3

11d-9-3≤15d             subtract 9 from both sides

11d -12 ≤ 15d

11d - 15d - 12≤ 0      subtract 12 from both sides

-4d     ≤ 12

d        ≥ 12÷ (-4)       change signs when dividing by negatives

d        ≥ -3

Hope it helps and if it does, please mark me brainliest...

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