All you need to know is that:
So, if sin theta is negative and cot theta is positive, you're saying that you're looking at a point with negative y coordinate and such that
[tex]\dfrac{\cos(\theta)}{\sin(\theta)}>0[/tex]
The ratio of two numbers is positive if and only if they have the same sign, so the cosine must by negative as well.
Saying that an angle has negative sine and cosine is the same as saying that the angle identifies a point on the unit circle where both x and y coordinates are negative.
So, if you look at the bullet list at the beginning, you'll see that the point is in the third quadrant.