Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Use technology or a z-distribution table to find the indicated area.

Suppose the distances from the center of a target that arrows strikes are normally distributed with a mean of 20 cm and a standard deviation of 6.4 cm.

Approximately 25% of the arrows are further than what distance from the center?

Answer 1

Answer:  b) 15.7

Step-by-step explanation:

Look at the z-table (below) to find 0.2500  

Notice that the value is not on the table but is between 0.2486 and 0.2517 which are located on the z-table at 0.67 and 0.68

The given value is closer to 0.2486 so use 0.67 as the z-score.

Now, let's find the x-value using the formula: $z=\dfrac{x-\mu}{\sigma}$

$-0.67=\dfrac{x-20}{6.4}\\\\\\\text{Multiply both sides by 6.4:}\\-4.288=x-20\\\\\\\text{Add 20 to both sides:}\\\large\boxed{15.712} = x$

Answer 2

The distance from the center will be 15.7 centimeters. Then the correct option is B.

What is a z-score?

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

Suppose the distances from the center of a target that arrows strike are normally distributed with a mean of 20 cm and a standard deviation of 6.4 cm.

If approximately 25% of the arrows are further than the distance from the center will be

The value of z-score for the 0.25 will be negative 0.67.

Then we have

- 0.67 = (x - 20)/6.4

-4.288 = x - 20

        x = 15.712

        x ≅ 15.7

Thus, the correct option is B.

More about the z-score link is given below.

https://brainly.com/question/15016913

#SPJ2