Square KITE has vertices (-4, 0), (0, 4), (4, 0), and (0, -4), respectively. Name the square's diagonals and find their point of intersection.

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hence the answer is 16units

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Ver imagen jyothi75

The equation of diagonals of kite are x = 0 and y = 0 and their point of intersection is (0,0)

What is a straight line?

A straight line is a one-dimensional figure that never ends and has no breadth.

Equation of line : y = mx + c

m - slope of the line

c - y intercept

Let the vertices of the Kite ABCD be A(-4 , 0), B(0 , 4), C(4 , 0), D(0 , -4)

The equation of Diagonal AC is y = 0

The equation of Diagonal BD is x = 0

The point of intersection of diagonals will be ( 0 , 0)

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