Respuesta :
Name m the money at the beggining of the first day. This table shows the money at the end of every day, after half the money has been removed
Day money
1Â Â Â m/2 = m/2^1
2Â Â Â m/4 = m/2^2
3Â Â Â m/8= m/2^3
4Â Â Â m/16= m/2^4
...
n    m/2^n
The model is m/2^n, where n is numbers of days elapsed and m is the money at the end of that day (after half on the money has been removed).
Day money
1Â Â Â m/2 = m/2^1
2Â Â Â m/4 = m/2^2
3Â Â Â m/8= m/2^3
4Â Â Â m/16= m/2^4
...
n    m/2^n
The model is m/2^n, where n is numbers of days elapsed and m is the money at the end of that day (after half on the money has been removed).
Answer: Exponential decay function
Step-by-step explanation:
Given: Each day 1/2 the money that is in the bank vault is removed. no money is added to the vault.
The constant ratio of decay = [tex]\frac{1}{2}[/tex]
- A function is said to be exponential decay function if it decreases at a rate proportional to its previous value.
Here the amount in the bank is decreasing at a constant ratio of  [tex]\frac{1}{2}[/tex].
Therefore, the exponential decay function models the situation.
