can anybody help me on this
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Answer:
[tex]8\sqrt{3}[/tex]
Step-by-step explanation:
Area of the triangle is given as:
[tex]\text{Area}=\frac{1}{2} \times \text{Base} \times \text{Height}\\\\ \text{Using the given values of Area and Base, we get:}\\\\ 8\sqrt{6} =\frac{1}{2}\times2\sqrt{2}\times\text{Height}\\\\ \frac{8\sqrt{6} \times 2}{2\sqrt{2} }=\text{Height}\\\\8\sqrt{3}=\text{Height}[/tex]
Thus the height of the triangle will be: [tex]8\sqrt{3}[/tex]
Answer:
The correct answer is third option
height =8√3
Step-by-step explanation:
Area of triangle = bh/2
where b - Base of triangle
h - Height of triangle
To find the height of triangle
It is given, b = 2√2 and h = 8√6
Area = bh/2
8√6 = (2√2 * h)/2
8√6 = √2 * h)
h = 8√6 /√2
h = 8√3
Therefore the correct answer is third option 8√3 in