Answer:
The ball reach the ground at t=4 sec
Step-by-step explanation:
Let
h-----> the height of the ball
t-----> the time in seconds
we have
[tex]h=-16t^{2} +250[/tex]
we know that
When the ball reach the ground h=0 (x-intercept of the function)
so
For h=0 ind the value of t
[tex]0=-16t^{2} +250[/tex]
[tex]16t^{2}=250[/tex]
[tex]t^{2}=15.625[/tex]
[tex]t=(+/-)4[/tex]
The solution is t=4 seconds ( the value of t can not be negative)