Question

whats the value of x

Answer 1

Answer:

$x=4\ units$

Step-by-step explanation:

step 1

Find the length of JL

In the right triangle KLJ

$sin(30\°)=\frac{JL}{8\sqrt{2}}$

$sin(30\°)=\frac{1}{2}$

so

$\frac{1}{2}=\frac{JL}{8\sqrt{2}}$

$JL=4\sqrt{2}\ units$

step 2

Find the value of x

In the right triangle JLM

$sin(45\°)=\frac{x}{4\sqrt{2}}$

$sin(45\°)=\frac{\sqrt{2}}{2}$

so

$\frac{\sqrt{2}}{2}=\frac{x}{4\sqrt{2}}$

$x=4\ units$