Question

The distance AB rounded to the nearest tenth =

Answer 1

it gives you the formula, so all you have to do is plug in the coordinates

$d = \sqrt{ {( - 1 + 3)}^{2} + {( - 1 - 1)}^{2} } \\ d = \sqrt{ {(2)}^{2} + {( - 2)}^{2} } \\ d = \sqrt{ 4 + 4 } \\ d = \sqrt{8} \\ d = 2 \sqrt{3} = 3.4641... \\ \\ d = 3.5$

Answer 2

The distance AB will be equal to 3.5 units.

What is coordinate geometry?

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The distance AB will be calculated by using the following formula:-

$AB =\sqrt{(-1+3)^2+((-1-1)^2}$

$AB = \sqrt{(20^2+(-2)^2}$

$AB =\sqrt{8}$

Ab = 2√3

AB = 3.5 units

Therefore the distance AB will be equal to 3.5 units.

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