Question

describe the nature of the roots for this equation.
3x^2 - 2x + 1 = 0

A. two real, rational roots
B. two real, irrational roots
C. one real, double root
D. two complex roots

Answer 1

Answer:

Option D. two complex roots

Step-by-step explanation:

we know that

In a quadratic equation of the form $ax^{2} +bx+c=0$ the discriminant D is equal to

$D=(b^{2}-4ac)$

in this problem we have

$3x^{2} -2x+1=0$  

so

$a=3\\b=-2\\c=1$

substitute the values

$D=(-2^{2}-4(3)(1))$

$D=(4-12)$

$D=-8$

The discriminant is negative

therefore

The quadratic equation has two complex roots