Answer:
1: z = 1.96
2: t = 2.552
Step-by-step explanation:
1: When you don't know the population standard deviation and the sample size is large, you can still use a z test because many large samples are relatively normally distributed. A 95% confidence interval uses a z-score of 1.96
2. We are told that n < 30, so we use t distribution. Use the degrees of freedom, which is one less than the population, and the column that has 0.02 in the area of 2 tails.