Question

what is the difference of the polynomials?
(-2x^3y^2 + 4x^2y^3 - 3xy^4) - (6x^4y - 5x^2y^3 - y^5)

Answer 1

Answer:

A

Step-by-step explanation:

I'm assuming you already know how to do it and just need an answer.

Answer 2

The difference of the polynomial will be $- 6x^4y-2x^3y^2 + 9x^2y^3 - 3xy^4 + y^5$

Given the polynomial function

$(-2x^3y^2 + 4x^2y^3 - 3xy^4) - (6x^4y - 5x^2y^3 - y^5)$

Expand the parenthesis to have:

$-2x^3y^2 + 4x^2y^3 - 3xy^4 - 6x^4y + 5x^2y^3 + y^5)$

Collect the like terms:

$-2x^3y^2 + 4x^2y^3 + 5x^2y^3- 3xy^4 - 6x^4y + y^5\\-2x^3y^2 + 9x^2y^3 - 3xy^4 - 6x^4y + y^5$

Rearrange:

$- 6x^4y-2x^3y^2 + 9x^2y^3 - 3xy^4 + y^5$

Hence the difference of the polynomial will be $- 6x^4y-2x^3y^2 + 9x^2y^3 - 3xy^4 + y^5$

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