Question

What volume would 20.0g of CO2 occupy at a temperature of 298k and a pressure of 105 kPa​

Answer 1

1. u divide the mass 20.0g by its molar mass of 44.01g/mol = 0.454mol

2. using the formula PV=nRT

105kPa x V = 0.454mol (use the non rounded value) x 8.314Lkpa/molK x 298K

V= 10.7L :)