Question

What is the equation of a line passing through (-3,7) and having a slip of -1/5
A.y=-5x+22
B.y=5x+33
C.y=1/5x+32/5
D.y=-1/5x+32/5
E.y=-1/5x+22

Answer 1

Answer:

$\large\boxed{D.\ y=-\dfrac{1}{5}x+\dfrac{32}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

$y=-\dfrac{1}{5}x+b$

Put the coordinates of the given point (-3, 7) to the equation:

$7=-\dfrac{1}{5}(-3)+b$

$7=\dfrac{3}{5}+b$            subtract 3/5 from both sides

$6\dfrac{2}{5}=b\to b=\dfrac{6\cdot5+2}{5}=\dfrac{32}{5}$