Answer:
a. [tex]x=-1,2,\:or\:6[/tex]
Step-by-step explanation:
The given equation is
[tex]x^3-7x^2+4x+12=0[/tex]
To find all real solutions using the x-intercept method, we to graph the corresponding function using a graphing tool.
The corresponding function is;
[tex]f(x)=x^3-7x^2+4x+12[/tex]
The real solutions to [tex]x^3-7x^2+4x+12=0[/tex], are the x-intercepts of the graph of the corresponding function.
From the graph the x-intercepts are
(-1,0),(2,0) and (6,0).
Therefore the real solutions are
[tex]x=-1,2,\:or\:6[/tex]
