Question

Identify the equation of the translated graph in general form x^2-y^2=8 for T(4,3)

Answer 1

Answer:

B

Step-by-step explanation:

A transformation of T(a,b) in the equation would give this form:

$(x-a)^2+(y-b)^2=8$

So, T(4,3) means translation of 4 units in x and 3 units in y. Thus, we can write:

$(x-4)^2+(y-3)^2=8$

Expanding and rearranging, we get:

$(x-4)^2-(y-3)^2-8=0\\x^2-8y+16-y^2+6y-9-8=0\\x^2-y^2-8x+6y-1=0$

Answer choice B is right.

Answer 2

Answer:

B

x^2-y^2-8x+6y-1=0