Question

A projectile is launched with a momentum of 200 kg •m/s and 1000 j of kinetic energy. What is the mass of the projectile?

Answer 1

Answer:

0.1 kg

Explanation:

The kinetic energy of an object is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is the speed of the object

The momentum of an object is given by

$p=mv$

which is the product of mass and speed.

We can combine the two equations to get an expression that relates the kinetic energy K to the momentum p:

$K=\frac{1}{2}m(\frac{p}{m})^2=\frac{p^2}{2m}$

In this problem, we know

$K=1000 J$ is the kinetic energy

$p=200 kg m/s$

So we can solve the formula for m to find the mass of the projectile:

$m=\frac{p^2}{2K}=\frac{(200 kg m/s)^2}{2(1000 J)}=20 kg$

Answer 2

The mass of the projectile object that has a kinetic energy of 1000 J and momentum of 200 kgm/s is 20 kg.

What is kinetic energy?

When a body of mass (m) and moving with the velocity (u) then the body possesses the energy and this energy is called kinetic energy.

A projectile is launched with a momentum of 200 kg m/s and 1000 J of kinetic energy.

We know that the equation of kinetic energy is given by

$\rm KE = \dfrac{1}{2} mu^2$...1

We know the momentum is given by

$\rm P = mu\\\\u = \dfrac{p}{m}$..2

From equations 1 and 2, we have

$\rm KE = \dfrac{1}{2} m(\dfrac{P}{m})^2\\\\KE = \dfrac{1}{2m} (P)^2\\\\m \ \ = \dfrac{P^2}{2*KE}$

Put the value of kinetic energy (KE) and momentum (P), we have

$\rm m = \dfrac{P^2}{2*KE}\\\\\\m = \dfrac{200^2}{2*1000}\\\\\\m = \dfrac{40000}{2000}\\\\\\m = 20$

The mass of the projectile object is 20 kg.

More about the kinetic energy link is given below.

https://brainly.com/question/999862