Respuesta :
Answer:
[tex]\frac{2y+3}{7y-1}[/tex]
Step-by-step explanation:
The given expression is
[tex]\frac{10y^2+15y}{35y^2-5y}[/tex]
Factor both the numerator and the denominator.
[tex]=\frac{5y(2y+3)}{5y(7y-1)}[/tex]
Cancel out the common factors.
[tex]=\frac{2y+3}{7y-1}[/tex]
Answer:
The correct answer is,
(10y² + 15y)/(35y² - 5y) = (2y + 3 )/( 7y - 1)
Step-by-step explanation:
It is given an expression,
(10y² + 15y)/(35y² - 5y)
To simplify the given expression
Taking 5y as common from both numerator and denominator,
(10y² + 15y )/( 35y² - 5y) = 5y( 2y + 3)/5y( 7y - 1)
= (2y + 3 )/( 7y - 1)
Therefore the simplified form of given expression is given by,
(10y² + 15y)/(35y² - 5y) = (2y + 3 )/( 7y - 1)