Question

Look at this linear equation. 3x + 5y = 30 Which of the following equations can be used to solve for y in the linear equation above? A. y = - x + 30 B. y = 3x + 6 C. y = - x + 6 D. y = x + 30

Answer 1

Answer:

$y=-\frac{3}{5} x+6$

Step-by-step explanation:

Lets solve the equation $3x+5y=30$ for $y$ step-by-step:

Step 1. Subtract $3x$ from both sides of the equation

$3x+5y=30$

$3x-3x+5y=-3x+30$

$5y=-3x+30$

Step 2. Divide both sides of the equation by 5

$\frac{5y}{5} =\frac{-3x+30}{5}$

$y=\frac{-3x+30}{5}$

$y=-\frac{3}{5}x+\frac{30}{5}$

$y=-\frac{3}{5} x+6$

We can conclude that the equation that can be used for solve for $y$ is $y=-\frac{3}{5} x+6$

Answer 2

Answer:

y = -3x/5 + 6

Step-by-step explanation:

Given the equation 3x+5y = 30, to find the equation that can be used to solve for y, we will have to make y the subject of the formula from the given linear equation to have;

3x + 5y = 30

First we will subtract 3x from both sides of the equation to have;

3x+5y-3x = 30-3x

5y = 30-3x

Dividing both sides of the equation by the coefficient of y which is 5 we will have;

5y/5 = 30/5-3x/5

y = 6-(3x/5)

y = -3x/5 + 6