Question

What are the zeros of f(x)=x^2-8x+16

Answer 1

Answer:

4 and 4

Step-by-step explanation:

The quadratic f(x)=x^2-8x+16 factors into f(x) = (x - 4)².

Setting this result = to 0, we obtain the double root x = 4, x = 4.

Answer 2

Answer:

zero of the function is 4

Step-by-step explanation:

$f(x)=x^2-8x+16$

To find the zeros , we replace f(x) with 0

$0=x^2-8x+16$

Factor the right side of the equation and solve for x

$0=x^2-8x+16$ product is 16 and sum is 8

-4 times -4 is 16

-4 plus -4 is -8, the factors are -4 and -4

$0=(x-4)(x-4)$

set each factor =0 and solve for x

x-4 =0, x=4