Question

The pressure of a sample of helium is 2.0 atm in a 200-mL container. If the container is compressed to 10 mL without changing the temperature, what is the new pressure?

Answer 1

Answer:

40 atm

Explanation:

Boyle’s law states that for a fixed amount of gas the pressure is inversely proportional to the volume of the gas at constant temperature.

P1V1 = P2V2

Where P1 is pressure and V1 is volume at the first instance

And P2 is pressure and V2 is volume at the second instance

Substituting the values in the equation

2.0 atm x 200 mL = P2 x 10 mL

P2 = 40 atm

The new pressure is 40 atm

Answer 2

The new pressure of the helium gas is 40 atm.

To calculate the new pressure of the helium, we use the formula below.

Formula:

• PV = P'V'.................. Equation 1

Where:

• P = Original pressure
• V = Original volume
• P' = New pressure
• V' = New volume.

Make P' the subject of the equation

• P' = PV/V'................ Equation 2

From the question,

Given:

• P = 2.0 atm
• V = 200 mL
• V' = 10 mL

Substitute these values into equation 2

• P' = (2×200)/10
• P' = 40 atm.

Hence, The new pressure of the helium gas is 40 atm.

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