1) Magnitude of the force: [tex]1.6\cdot 10^{-12} N[/tex]
The magnitude of the electric force on an electric charge is:
[tex]F=qE[/tex]
where q is the charge and E the electric field. In this problem:
[tex]q = +e = +1.6\cdot 10^{-19} C[/tex] is the charge of the calcium ion
[tex]E=1.0 \cdot 10^7 N/C[/tex] is the magnitude of the electric field
Substituting,
[tex]F=(1.6\cdot 10^{-19}C)(1.0\cdot 10^7 N/C)=1.6\cdot 10^{-12} N[/tex]
2) Acceleration: [tex]2.5\cdot 10^{13} m/s^2[/tex]
The atomic mass of a calcium ion is approx. 40 a.m.u, this means that its mass is
[tex]m=40 \cdot (1.6\cdot 10^{-27}kg)=6.4\cdot 10^{-26} kg[/tex]
And so, the acceleration of the ion is given by Newton's second law:
[tex]a=\frac{F}{m}=\frac{1.6\cdot 10^{-12}N}{6.4\cdot 10^{-26} kg}=2.5\cdot 10^{13} m/s^2[/tex]
3) Yes
Explanation: a particle with same charge (+e) of the calcium ion could have the same acceleration of the calcium ion if it has exactly the same mass. In fact, the acceleration depends only on two factors: the mass and the force, so it both are the same, than the acceleration does not change.
4) The mass of the particle
In fact, the acceleration of the particle is given by:
[tex]a=\frac{F}{m}[/tex]
where F is the electric force and m the mass. Therefore, if the mass changes ,the acceleration changes as well.
A particle with the same mass and charge as calcium could have a different acceleration.
Let us recall that the electric field strength is the magnitude of the electric field at a point. Mathematically;
F = qE
F = electric force
q = charge on the +e ion
E electric field strength
F = 1.0 x 10^7 N/C x 1.6 x 10^-19 C
F = 1.6 x 10^-12 N
Since;
F = ma
a = F/m = 1.6 x 10^-12 N/40(1.6 x 10^-27)
a = 2.5 x 10^13 ms-2
A particle with the same mass and charge as calcium could have a different acceleration. If the mass of the particle changes, the acceleration of the particle changes as also.
Learn more about mass and charge: https://brainly.com/question/8139015
