Answer:
[tex]\frac{32}{5}[/tex].
Step-by-step explanation:
We have been given a system of equations and we are asked to find the value of y in the solution to the given system.
[tex]x+y=1...(1)[/tex]
[tex]2x-3y=-30...(2)[/tex]
To solve our given system of equation, we will use substitution method. From equation (1) we will get,
[tex]x=1-y[/tex]
Upon substituting this value in equation (2), we will get:
[tex]2(1-y)-3y=-30[/tex]
Using distributive property, we will get:
[tex]2-2y-3y=-30[/tex]
[tex]2-5y=-30[/tex]
[tex]2-2-5y=-30-2[/tex]
[tex]-5y=-32[/tex]
Now, we will divide both sides of our equation by -5.
[tex]\frac{-5y}{-5}=\frac{-32}{-5}[/tex]
[tex]y=\frac{32}{5}[/tex]
Therefore, the value of y is [tex]\frac{32}{5}[/tex].