Respuesta :
Answer:
option D
[tex]\frac{4x-8}{-2x^2}[/tex]
Step-by-step explanation:
An expression is undefined when you get division by zero or in simple words when denominator is zero.
Now we will solve each expression one be one by plugging value of x = 0
1)
[tex]\frac{5x^2-4}{3x-3}[/tex]
[tex]\frac{5(0)-4)}{3(0)-3}[/tex]
-4/-3 = 4/3
2)
[tex]\frac{6x^2}{9x-3}[/tex]
[tex]\frac{6(0)}{9(0)-3}[/tex]
0/-3 = 0
3)
[tex]\frac{8x+6}{-x^2+1}[/tex]
[tex]\frac{8(0)+6}{-0+1}[/tex]
6/1
6
4)
[tex]\frac{4x-8}{-2x^2}[/tex]
[tex]\frac{4(0)-8}{-2(0)}[/tex]
-8/0
undefined