Question

Help??????? It’s precal

Answer 1

what does precal mean I don't understand

Answer 2

ANSWER

$\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}$

EXPLANATION

The given functions are:

$F(x)=2x$

and

$G(x)= {x}^{2} + 2$

$\frac{F}{G} (x) = \frac{F(x)}{G(x)}$

$\frac{F}{G} (x) = \frac{2x}{ {x}^{2} + 2 }$

Substitute x=-1

$\frac{F}{G} ( - 1) = \frac{2( - 1)}{ {( - 1)}^{2} + 2 }$

$\frac{F}{G} ( - 1) = \frac{ - 2}{ 1+ 2 }$

$\frac{F}{G} ( - 1) = - \frac{ 2}{ 3}$

The first choice is correct.