What is the area of this figure? Please help

Answer:
Step-by-step explanation:
The square has 4 sides with length 4
The right triangle has the right side equal to 4yd + 4yd(from the square) = 8yd
Using the Pythagorean Theorem, we find that the left side of the triangle has length = 10yd
The area of the whole thing is the area of the square + the area of the triangle
The formula for the area of a square with sides l is [tex]A_s = l^2[/tex]
The area of the triangle is trickier, but you can imagine tracing a line in the left side and the upper side to form a rectangle, and the area of that is A = [tex]l * L[/tex], the area of the triangle will be half the area of the rectangle so it'll be [tex]A = \frac{6 * 8}{2} = 24 (yd)^{2}[/tex]
The total area will be;
Area of the square + Area of the triangle = [tex]16 + 24 = 40 yd^{2}[/tex]