Answer: [tex]\bold{\dfrac{3\pm \sqrt{65}}{14}}[/tex]
Step-by-step explanation:
[tex]7x^2-3x=2\quad \rightarrow \quad 7x^2-3x-2=0\quad \rightarrow \quad a=7,\ b=-3,\ c=-2\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(7)(-2)}}{2(7)}\\\\\\.\ =\dfrac{3\pm \sqrt{9+56}}{14}\\\\\\.\ =\dfrac{3\pm \sqrt{65}}{14}[/tex]
