ria2389
ria2389 ria2389
  • 31-03-2019
  • Mathematics
contestada

Plz help me!!!!!!!!!

Plz help me class=

Respuesta :

DeanR
DeanR DeanR
  • 31-03-2019

[tex]\sqrt[3]{x^2y^2} = (x^2y^2)^{\frac 1 3} = x^{\frac 2 3}y ^{\frac 2 3}[/tex]

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tramserran
tramserran tramserran
  • 31-03-2019

Answer:  [tex]\bold{x^{\frac{2}{3}}y^{\frac{2}{3}}}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{x^2y^2}=\sqrt[3]{(xy)^2}=(xy)^{\frac{2}{3}}=x^{\frac{2}{3}}y^{\frac{2}{3}}[/tex]

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